Buck Hill (Herkimer County, New York)
Buck Hill is a summit located in Central New York Region of New York located in the Town of Russia in Herkimer County, north of Poland.
| Buck Hill | |
|---|---|
Buck Hill Location of Buck Hill within New York Buck Hill Buck Hill (the United States) | |
| Highest point | |
| Elevation | 928 feet (283 m) |
| Coordinates | 43°14′13″N 75°03′31″W[1] |
| Geography | |
| Location | N of Poland, New York, U.S. |
| Topo map | USGS Newport |
References
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