1824 Maryland gubernatorial election
The 1824 Maryland gubernatorial election was held on 13 December 1824 in order to elect the Governor of Maryland. Incumbent Democratic-Republican Governor Samuel Stevens Jr. was re-elected by the Maryland General Assembly against former Federalist Governor Charles Goldsborough, Democratic-Republican candidate Roger B. Taney and Federalist candidates Robert Henry Goldsborough and John Eager Howard.[1]
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| Elections in Maryland |
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| Government |
General election
On election day, 13 December 1824, incumbent Democratic-Republican Governor Samuel Stevens Jr. was re-elected by the Maryland General Assembly, thereby retaining Democratic-Republican control over the office of governor. Stevens was sworn in for his third term on 3 January 1825.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Samuel Stevens Jr. (incumbent) | 67 | 85.90 | |
| Did Not Vote | 5 | 6.41 | ||
| Federalist | Charles Goldsborough | 3 | 3.85 | |
| Democratic-Republican | Roger B. Taney | 1 | 1.28 | |
| Federalist | Robert Henry Goldsborough | 1 | 1.28 | |
| Federalist | John Eager Howard | 1 | 1.28 | |
| Total votes | 78 | 100.00 | ||
| Democratic-Republican hold | ||||
References
- "Samuel Stevens Jr". National Governors Association. Retrieved 27 April 2024.
- "MD Governor". ourcampaigns.com. 26 August 2004. Retrieved 27 April 2024.
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