1826 Ohio gubernatorial election
The 1826 Ohio gubernatorial election was held on 10 October 1826, in order to elect the Governor of Ohio. National Republican candidate and former Acting Governor Allen Trimble defeated Democratic-Republican candidates Alexander Campbell, Benjamin Tappan and John Bigger.[1]
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| Elections in Ohio |
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General election
On election day, 10 October 1826, National Republican candidate Allen Trimble won the election by a margin of 66,710 votes against his foremost opponent Democratic-Republican candidate Alexander Campbell, thereby gaining National Republican control over the office of Governor. Trimble was sworn in as the 10th Governor of Ohio on 19 December 1826.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| National Republican | Allen Trimble | 71,475 | 84.35% | |
| Democratic-Republican | Alexander Campbell | 4,765 | 5.62% | |
| Democratic-Republican | Benjamin Tappan | 4,192 | 4.95% | |
| Democratic-Republican | John Bigger | 4,114 | 4.86% | |
| Scattering | 187 | 0.22% | ||
| Total votes | 84,733 | 100.00% | ||
| National Republican gain from Democratic-Republican | ||||
References
- "Allen Trimble". National Governors Association. Retrieved 10 May 2024.
- "OH Governor". ourcampaigns.com. 18 February 2005. Retrieved 10 May 2024.
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