2018 Mumbai Open – Doubles

Natela Dzalamidze and Veronika Kudermetova won the title, defeating Schoofs and Barbora Štefková in the final, 6–4, 7–6(7–4).[1]

Doubles
2018 Mumbai Open
Champion Natela Dzalamidze
Veronika Kudermetova
Runner-up Bibiane Schoofs
Barbora Štefková
Score6–4, 7–6(7–4)

Victoria Rodríguez and Bibiane Schoofs were the defending champions, but Rodríguez chose not to participate this year.

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 D Jakupović
I Khromacheva
6 6
S Shapatava
E Webley-Smith
0 2 1 D Jakupović
I Khromacheva
6 6
R Bhosale
H Kuwata
7 3 [11] R Bhosale
H Kuwata
3 3
T Mrdeža
A Raina
5 6 [9] 1 D Jakupović
I Khromacheva
5 3
3 N Dzalamidze
V Kudermetova
6 6 3 N Dzalamidze
V Kudermetova
7 6
WC M Jain
M Yadav
1 1 3 N Dzalamidze
V Kudermetova
6 6
M Doi
T Martincová
6 4 [10] M Doi
T Martincová
1 1
V Grammatikopoulou
Jia Lu
2 6 [4] 3 N Dzalamidze
V Kudermetova
6 77
L Kumkhum
P Thombare
2 6 [7] 4 B Schoofs
B Štefková
4 64
S-y Hsieh
N Kostić
6 2 [10] S-y Hsieh
N Kostić
6 63 [5]
E Gorgodze
D Khazaniuk
4 62 4 B Schoofs
B Štefková
1 77 [10]
4 B Schoofs
B Štefková
6 77 4 B Schoofs
B Štefková
3 77 [10]
K-y Ng
S Zheng
4 63 O Danilović
D Kovinić
6 65 [8]
O Danilović
D Kovinić
6 77 O Danilović
D Kovinić
6 6
K Palkina
Y Sizikova
1 1 2 N Hibino
O Kalashnikova
2 1
2 N Hibino
O Kalashnikova
6 6

References

  1. "Kumkhum comeback brings her biggest career title in Mumbai". WTA. 4 November 2018. Retrieved 29 June 2022.
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